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Qn #577
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The two parabolas $y^2 = 4a(x + c)$ and $y^2 = 4bx, a > b > 0$ cannot have a common normal unless
A.
$$c>2(a+b)$$
B.
$$c>(a-b)$$
C.
$$c<2(a-b)$$
D.
$$c<\frac{2}{a-b}$$
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❓ Question: The two parabolas $y^2 = 4a(x + c)$ and $y^2 = 4bx... | TANCET Group Studies | Tancet Group Studies