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Question 1
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The slope of the normal line to the curve $x = t^2 + 3t - 8$ and $y = 2t^2 - 2t - 5$ at the point (2,-1) is
A.
$\frac{22}{7}$
B.
$\frac{-7}{6}$
C.
-5
D.
$\frac{-6}{7}$
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