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Qn #863
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The eccentric angle of the extremities of latus-rectum of the ellipse $\frac{{x}^2}{{a}^2}^{}+\frac{{y}^2}{{b}^2}^{}=1$ are given by
A.
$\tan ^{-1}(\pm\frac{ae}{b})$
B.
$\tan ^{-1}(\pm\frac{be}{e})$
C.
$\tan ^{-1}(\pm\frac{b}{ae})$
D.
$\tan ^{-1}(\pm\frac{a}{be})$
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❓ Question: The eccentric angle of the extremities of latus-re... | TANCET Group Studies | Tancet Group Studies