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Qn #845
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If $y={\tan }^{-1}\lgroup{\frac{3x-{x}^3}{1-3{x}^2}}\rgroup\, ,\, \frac{-1}{\sqrt[]{3}}{\lt}x{\lt}\frac{1}{\sqrt[]{3}}$ then $\frac{dy}{dx}$ is
A.
$\frac{-1}{1+{x}^2}$
B.
$\frac{3}{1+{x}^2}$
C.
$\frac{3}{\sqrt[]{1+\{x\}^2}}$
D.
$\frac{1}{\sqrt[]{1+\{x\}^2}}$
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❓ Question: If $y={\tan }^{-1}\lgroup{\frac{3x-{x}^3}{1-3{x}^2... | TANCET Group Studies | Tancet Group Studies