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Question 1
If the foci of the ellipse $b^{2}x^{2}+16y^{2}=16b^{2}$ and the hyperbola $81x^{2}-144y^{2}=\frac{81 \times 144}{25}$ coincide, then the value of $b$, is
A.
$1$
B.
$\sqrt{5}$
C.
$\sqrt{7}$
D.
$3$
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