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Qn #478
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If $\cos^2(10°)\cos(20°)\cos(40°)\cos(50°) \cos(70°) = \alpha+\frac{\sqrt{3}}{16} \cos(10°)$, then $3\alpha^{-1}$ is equal to
A.
$\frac{9}{32}$
B.
64
C.
16
D.
$\frac{9}{16}$
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❓ Question: If $\cos^2(10°)\cos(20°)\cos(40°)\cos(50°) \cos(70... | TANCET Group Studies | Tancet Group Studies