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Qn #1424
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If (2, 1), (–1, –2), (3, 3) are the midpoints of the sides BC, CA, AB of a triangle ABC, then equation of the line BC is
A.
5x + 4y + 6 = 0
B.
5x – 4y – 6 = 0
C.
5x + 4y – 6 = 0
D.
5x – 4y + 6 = 0
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❓ Question: If (2, 1), (–1, –2), (3, 3) are the midpoints of t... | TANCET Group Studies | Tancet Group Studies