TANCET
Group Studies
Mock Tests
Notes
Library
Join Now
Question Practice
Share
Target (sec):
00:00
Question 1
Share
Given the equation $x+y =1$, $x^2+y^2 =2$, $x^5 +y^5 =A$. Let N be the number of solution pairs (x,y) to this system of equations. Then AN is equal to
A.
$$\frac{7}{2}$$
B.
$$3$$
C.
$$\frac{19}{2}$$
D.
$$2$$
Discussion
Join the Conversation
Log in to post comments and replies.
Log In
Open Discussion
❓ Question: Practice this question with detailed solutions and... | TANCET Group Studies | Tancet Group Studies