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Qn #1174
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Equation of the common tangents with a positive slope to the circle $x^2+y^2-8x=0$ and$\dfrac{x^2}{9}-\dfrac{y^2}{4}=1$ is
A.
2x-$\sqrt5$y-20=0
B.
2x-$\sqrt5$y+4=0
C.
3x-4y+8=0
D.
4x-3y+4=0
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❓ Question: Equation of the common tangents with a positive sl... | TANCET Group Studies | Tancet Group Studies